/*
Validate Binary Search Tree
===========================

Given the root of a binary tree, determine if it is a valid binary search tree (BST).

A valid BST is defined as follows:

The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.

Example 1:
Input: root = [2,1,3]
Output: true

Example 2:
Input: root = [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value is 4.

Constraints:
The number of nodes in the tree is in the range [1, 104].
-231 <= Node.val <= 231 - 1
*/

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */

class Solution
{
public:
  bool isValidBST(TreeNode *root)
  {
    return check(root, LONG_MIN, LONG_MAX);
  }

  bool check(TreeNode *root, long min, long max)
  {
    if (!root)
      return true;
    if (root->val <= min || root->val >= max)
      return false;
    return check(root->left, min, root->val) && check(root->right, root->val, max);
  }
};
